Can you make them fit?
Fill a 7 × 7 board with seven rectangles. Each must have perimeter 12.
The clock starts when you reveal the puzzle.THE SPACE INSIDE A BOUNDARY
Seven rectangles.
One shared boundary length.
Tap two corner cells, or drag to draw a rectangle.
A brain snack, with room to think.
THE ANSWER OPENS ANOTHER DOOR
You have an answer. Explore how it works, then take the idea somewhere new.
See why it works ↓THE IDEA BEHIND YOUR ANSWER
Your rectangles all measure 12 units around their edges. Inside, they tell a different story. Explore the pieces in your own arrangement.
FOLLOW THE BOUNDARY
Perimeter counts the distance around a shape. Area counts the space inside it. Equal perimeters can enclose different areas.
TRY CHANGING THE SHAPE
A rectangle has perimeter 2 × (width + height). For a perimeter of 12, width + height must be 6.
Slide from long and narrow to square, then back again. Turning a rectangle around changes its orientation, not its shape.
WHY YOUR MIX OF PIECES WAS INEVITABLE
With whole-number sides adding to 6, there are only three shapes up to rotation: 1 × 5, 2 × 4 and 3 × 3. Their areas are 5, 8 and 9.
If all seven pieces were 1 × 5, they would cover only 35 of the board’s 49 cells. We need 14 more.
Replacing a 1 × 5 with a 2 × 4 adds 3 cells. Replacing it with a 3 × 3 adds 4 cells.
The only whole-number solution to 3b + 4c = 14 is b = 2, c = 2. That leaves three of the smallest pieces.
So every valid board has three 1 × 5 rectangles, two 2 × 4 rectangles and two 3 × 3 squares. Here is the count from your arrangement:
| Shape | Count | Perimeter | Area each | Cells covered |
|---|---|---|---|---|
| Total | 7 | 12 each | — | 49 |
Area fixes the mix. Your drawing shows that the pieces can actually fit. Matching the total area alone would not prove that a tiling exists.
The idea to take away
When a packing puzzle feels like guesswork, count the area before arranging the pieces. One measurement can reveal what another leaves open.